Question

fran can lift 300 pounds of hay into her 15 - foot loft in 10 minutes. how much power is required to complete this task? (3 points)

Explanation:

Step1: Calculate work done

Work $W = \text{Force} \times \text{Distance} = 300\ \text{lb} \times 15\ \text{ft} = 4500\ \text{ft-lb}$

Step2: Convert time to seconds

$t = 10\ \text{min} \times 60 = 600\ \text{s}$

Step3: Calculate power (ft-lb/s)

Power $P = \frac{W}{t} = \frac{4500\ \text{ft-lb}}{600\ \text{s}} = 7.5\ \text{ft-lb/s}$

Step4: (Optional) Convert to horsepower

$1\ \text{hp} = 550\ \text{ft-lb/s}$, so $P = \frac{7.5}{550} \approx 0.0136\ \text{hp}$

Answer:

7.5 foot-pounds per second (or approximately 0.014 horsepower)