Question

the function f is defined by the following rule.
$f(x) = 4x - 1$
complete the function table.
(the table has x values -4, -1, 1, 2, 4 and corresponding f(x) blanks to fill.)

Explanation:

Step1: For \( x = -4 \)

Substitute \( x = -4 \) into \( f(x) = 4x - 1 \).
\( f(-4) = 4\times(-4) - 1 = -16 - 1 = -17 \)

Step2: For \( x = -3 \)

Substitute \( x = -3 \) into \( f(x) = 4x - 1 \).
\( f(-3) = 4\times(-3) - 1 = -12 - 1 = -13 \)

Step3: For \( x = 1 \)

Substitute \( x = 1 \) into \( f(x) = 4x - 1 \).
\( f(1) = 4\times1 - 1 = 4 - 1 = 3 \)

Step4: For \( x = 2 \)

Substitute \( x = 2 \) into \( f(x) = 4x - 1 \).
\( f(2) = 4\times2 - 1 = 8 - 1 = 7 \)

Step5: For \( x = 4 \)

Substitute \( x = 4 \) into \( f(x) = 4x - 1 \).
\( f(4) = 4\times4 - 1 = 16 - 1 = 15 \)

Answer:

For \( x = -4 \), \( f(x) = -17 \); for \( x = -3 \), \( f(x) = -13 \); for \( x = 1 \), \( f(x) = 3 \); for \( x = 2 \), \( f(x) = 7 \); for \( x = 4 \), \( f(x) = 15 \)

Filling the table:

\( x \)	\( f(x) \)
\( -3 \)	\( -13 \)
\( 1 \)	\( 3 \)
\( 2 \)	\( 7 \)
\( 4 \)	\( 15 \)