Question

is the function k(x) even, odd, or neither?

Explanation:

Step1: Recall even function definition

A function $k(x)$ is even if its graph is symmetric about the $y$-axis, meaning $k(-x) = k(x)$ for all $x$ in the domain.

Step2: Check graph symmetry

Observe the graph: for every point $(x, y)$ on $k(x)$, the point $(-x, y)$ also lies on $k(x)$. The graph is a mirror image across the $y$-axis.

Answer:

The function $k(x)$ is even.