Question

the functions q and r are defined as follows.
q(x) = -x + 1
r(x) = x² + 2
find the value of r(q(3)).
r(q(3)) = \boxed{}

Explanation:

Step1: Calculate q(3)

$q(3) = -3 + 1 = -2$

Step2: Substitute into r(x)

$r(q(3)) = r(-2) = (-2)^2 + 2$

Step3: Compute final value

$(-2)^2 + 2 = 4 + 2 = 6$

Answer:

6