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Question
- gay - lussac’s law
$\frac{p_1}{t_1}=\frac{p_2}{t_2}$ (solve for $t_1$)
$p_1$ = initial pressure
$t_1$ = initial absolute temperature
$p_2$ = final pressure
$t_2$ = final absolute temperature
Step1: Cross - multiply
$P_1T_2 = P_2T_1$
Step2: Solve for $T_1$
$T_1=\frac{P_1T_2}{P_2}$
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$T_1=\frac{P_1T_2}{P_2}$