Question

geometry hon - garcia (lms)
2 - 4: teacher_s_slope_parallel lines_p8 (lms graded)
slope of p=
slope of q=
slope of r=
slope of m=
slope of n=

Explanation:

Step1: Recall slope formula

The slope formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$, where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.

Step2: Find slope of line $p$ (assuming two - point method)

Let's assume two points on line $p$ are $(0,0)$ and $(4, - 12)$. Then $m_p=\frac{-12 - 0}{4 - 0}=\frac{-12}{4}=-3$.

Step3: Find slope of line $q$ (assuming two - point method)

Let's assume two points on line $q$ are $(0.4,-3)$ and $(12,0)$. Then $m_q=\frac{0+3}{12 - 0.4}=\frac{3}{11.6}=\frac{30}{116}=\frac{15}{58}$.

Step4: Find slope of line $r$ (assuming two - point method)

Let's assume two points on line $r$ are $(0,0)$ and $(-5,-6.8)$. Then $m_r=\frac{-6.8-0}{-5 - 0}=\frac{-6.8}{-5}=1.36$.

Step5: Find slope of line $m$

Since line $m$ is a horizontal line, for any two points $(x_1,y_1)$ and $(x_2,y_2)$ on it, $y_1=y_2$. So the slope $m_m = 0$.

Step6: Find slope of line $n$

Let's assume two points on line $n$ are $(-5,-6.8)$ and $(0.4,-3)$. Then $m_n=\frac{-3 + 6.8}{0.4+5}=\frac{3.8}{5.4}=\frac{38}{54}=\frac{19}{27}$.

Answer:

slope of $p=-3$
slope of $q=\frac{15}{58}$
slope of $r = 1.36$
slope of $m = 0$
slope of $n=\frac{19}{27}$