QUESTION IMAGE
Question
given: bcde is a parallelogram, ∠bae ≅ ∠cde, overline{ae} ≅ overline{cd} prove: △ abe is equilateral drag each necessary statement to the table to complete the proof. statements reasons bcde is a parallelogram, ∠bae ≅ ∠cde, overline{ae} ≅ overline{cd} given opposite sides of a parallelogram are congruent transitive property corresponding angles theorem transitive property converse of isosceles triangle theorem transitive property △ abe is equilateral definition of equilateral overline{ae} ≅ overline{be} overline{bc} ≅ overline{ed} overline{be} ≅ overline{ab} overline{cd} ≅ overline{be} overline{ae} ≅ overline{be} ≅ overline{ab} ∠bae ≅ ∠bea ∠bcd ≅ ∠deb ∠cde ≅ ∠bea ∠cde ≅ ∠ebc overline{cd} ≅ overline{be} ≅ overline{ab} question #31
Step1: Match parallelogram side congruence
$\overline{BC} \cong \overline{ED}$, $\overline{CD} \cong \overline{BE}$
Step2: Transitive property for $\overline{AE} \cong \overline{BE}$
Given $\overline{AE} \cong \overline{CD}$ and $\overline{CD} \cong \overline{BE}$, so $\overline{AE} \cong \overline{BE}$
Step3: Corresponding angles from parallelogram
Since $BC \parallel ED$, $\angle CDE \cong \angle BEA$
Step4: Transitive property for $\angle BAE \cong \angle BEA$
Given $\angle BAE \cong \angle CDE$ and $\angle CDE \cong \angle BEA$, so $\angle BAE \cong \angle BEA$
Step5: Converse of isosceles triangle theorem
From $\angle BAE \cong \angle BEA$, $\overline{BE} \cong \overline{AB}$
Step6: Transitive property for all sides congruent
From $\overline{AE} \cong \overline{BE}$ and $\overline{BE} \cong \overline{AB}$, so $\overline{AE} \cong \overline{BE} \cong \overline{AB}$
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The completed proof table is:
| Statements | Reasons |
|---|---|
| $\overline{CD} \cong \overline{BE}$ | Opposite sides of a parallelogram are congruent |
| $\overline{AE} \cong \overline{BE}$ | Transitive Property |
| $\angle CDE \cong \angle BEA$ | Corresponding Angles Theorem |
| $\angle BAE \cong \angle BEA$ | Transitive Property |
| $\overline{BE} \cong \overline{AB}$ | Converse of Isosceles Triangle Theorem |
| $\overline{AE} \cong \overline{BE} \cong \overline{AB}$ | Transitive Property |
| $\triangle ABE$ is equilateral | Definition of Equilateral |