Question

1. given the equation: $_{6}^{14}c

ightarrow_{7}^{14}n + x$, what is the name of the particle is represented by the letter x? 4. the decay series of uranium - 235 is $alpha,\beta$. write an equation for each step in this decay series. 5. what is the difference between fusion and fission? fission involves splitting big, heavy atoms into smaller, lighter ones. fusion involves combining little atoms into bigger ones.

Explanation:

3.

Step1: Balance mass - number and atomic - number

In a nuclear reaction, the sum of mass - numbers and atomic - numbers on both sides of the equation must be equal. The mass - number of $^{14}_6C$ is 14 and its atomic - number is 6. The mass - number of $^{14}_7N$ is 14 and its atomic - number is 7. Let the mass - number of $X$ be $A$ and atomic - number be $Z$. Then, for mass - numbers: $14=14 + A$, so $A = 0$. For atomic - numbers: $6=7+Z$, so $Z=- 1$.

Step2: Identify the particle

A particle with mass - number 0 and atomic - number - 1 is a beta particle ($\beta^-$). The symbol for a beta particle is $_{-1}^0e$.

In $\alpha$ - decay, an $\alpha$ - particle ($^{4}_{2}He$) is emitted. The mass - number of the parent nucleus decreases by 4 and the atomic - number decreases by 2.

In $\beta$ - decay, a beta particle ($_{-1}^0e$) is emitted. The mass - number of the parent nucleus remains the same and the atomic - number increases by 1.

Answer:

Beta particle

4.

Uranium - 235 ($^{235}_{92}U$) can undergo $\alpha$ - decay and $\beta$ - decay.
$\alpha$ - decay: