Question

given the matrices a and b shown below, find b - a.
a = \

$$\begin{bmatrix} 3 & -5 \\\\ -5 & -5 \\\\ 0 & 4 \\\\ 1 & -1 \\end{bmatrix}$$

\quad b = \

$$\begin{bmatrix} 0 & -4 \\\\ 3 & 1 \\\\ -2 & 4 \\\\ 5 & -1 \\end{bmatrix}$$

answer attempt 1 out of 2
rows: 4 \\(-\\) \\(+\\) \quad columns: 2 \\(-\\) \\(+\\)
\

$$\begin{bmatrix} \\square & \\square \\\\ \\square & \\square \\\\ \\square & \\square \\\\ \\square & \\square \\end{bmatrix}$$

Explanation:

Step1: Subtract corresponding entries

To find $B-A$, subtract each entry of $A$ from the corresponding entry of $B$.

Step2: Calculate row 1 entries

Row 1, Column 1: $0 - 3 = -3$
Row 1, Column 2: $-4 - (-5) = 1$

Step3: Calculate row 2 entries

Row 2, Column 1: $3 - (-5) = 8$
Row 2, Column 2: $1 - (-5) = 6$

Step4: Calculate row 3 entries

Row 3, Column 1: $-2 - 0 = -2$
Row 3, Column 2: $4 - 4 = 0$

Step5: Calculate row 4 entries

Row 4, Column 1: $5 - 1 = 4$
Row 4, Column 2: $-1 - (-1) = 0$

Step6: Compile the resulting matrix

Assemble the calculated entries into a 4x2 matrix.

Answer:

$$\begin{bmatrix} -3 & 1 \\ 8 & 6 \\ -2 & 0 \\ 4 & 0 \end{bmatrix}$$