Question

graph the function $f(x) = -x^2$.
plot the vertex. then plot another point on the parabola. if you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first.

Explanation:

Step1: Identify the vertex

For $f(x) = -x^2$, compare to vertex form $f(x)=a(x-h)^2+k$ where $(h,k)$ is vertex. Here $h=0, k=0$, so vertex is $(0,0)$.

Step2: Find a second point

Choose $x=2$, substitute into $f(x)$:
$f(2) = -(2)^2 = -4$
So the point is $(2,-4)$.

Step3: Use symmetry for third point

Parabola is symmetric over y-axis, so if $(2,-4)$ is on it, $(-2,-4)$ is also on it.

Answer:

1. Plot the vertex at $(0, 0)$.
2. Plot the point $(2, -4)$ (and $(-2, -4)$ for symmetry).
3. Draw a downward-opening parabola passing through these points.