Question

graph the image of parallelogram bcde after a rotation 270° counterclockwise around the origin.

Explanation:

Step1: Recall rotation rule

The rule for a 270° counter - clockwise rotation around the origin is $(x,y)\to(y, - x)$.

Step2: Identify vertices of parallelogram

Let's assume the coordinates of the vertices of parallelogram $BCDE$ are $B(x_1,y_1)$, $C(x_2,y_2)$, $D(x_3,y_3)$, $E(x_4,y_4)$.

Step3: Apply rotation rule to each vertex

For vertex $B(x_1,y_1)$, the new coordinates $B'(y_1,-x_1)$. For vertex $C(x_2,y_2)$, the new coordinates $C'(y_2,-x_2)$. For vertex $D(x_3,y_3)$, the new coordinates $D'(y_3,-x_3)$. For vertex $E(x_4,y_4)$, the new coordinates $E'(y_4,-x_4)$.

Step4: Plot new vertices

Plot the new vertices $B'$, $C'$, $D'$, $E'$ on the coordinate plane and connect them to form the rotated parallelogram.

Answer:

Graph the new parallelogram formed by the rotated vertices as described above. (Since the actual coordinates of $B$, $C$, $D$, $E$ are not given numerically, a numerical answer for the new coordinates cannot be provided, but the steps to find and graph them are as above).