Question

graph the image of square difg after a dilation with a scale factor of 2, centered at the origin.

Explanation:

Step1: Identify original coordinates

Original square vertices: $G(5,5)$, $I(5,-5)$, $F(-5,-5)$, $D(-5,5)$

Step2: Apply dilation formula

Dilation rule: $(x,y)\to(2x,2y)$

• $G'(2\times5, 2\times5)=(10,10)$
• $I'(2\times5, 2\times(-5))=(10,-10)$
• $F'(2\times(-5), 2\times(-5))=(-10,-10)$
• $D'(2\times(-5), 2\times5)=(-10,10)$

Step3: Plot new vertices

Connect $G'(10,10)$, $I'(10,-10)$, $F'(-10,-10)$, $D'(-10,10)$

Answer:

The vertices of the dilated square are $G'(10,10)$, $I'(10,-10)$, $F'(-10,-10)$, $D'(-10,10)$. When plotted and connected, these form the image of the square after dilation.