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Question
- the graph of a linear equation has a slope of -2 and passes through point (-4, 3). what is the equation of the line? y = -2x + 2 y = -2x + 5 y = -2x - 2 y = -2x - 5 clear all
Step1: Use slope-intercept form
$y = mx + b$, $m=-2$, so $y=-2x + b$
Step2: Substitute point (-4,3)
$3 = -2(-4) + b$ → $3 = 8 + b$
Step3: Solve for b
$b = 3 - 8 = -5$
Step4: Form equation
$y = -2x -5$
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D. $y = -2x -5$