Question

graph the parabola $y = \frac{3}{4}x^2$. plot the vertex. then plot another point on the parabola. if you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first. graph with x-axis from -10 to 10 and y-axis from -10 to 10, grid lines, and a submit button

Explanation:

Step1: Find the vertex

For $y=ax^2$, vertex is $(0,0)$.

Step2: Pick x, solve for y

Let $x=4$: $y=\frac{3}{4}(4)^2=\frac{3}{4}(12)=9$? No, $\frac{3}{4}(16)=12$. Wait, simpler $x=2$: $y=\frac{3}{4}(2)^2=\frac{3}{4}(4)=3$. So point $(2,3)$.

Step3: Use symmetry for left point

Parabola is symmetric over y-axis, so $(-2,3)$ is also on the curve.

Answer:

1. Plot the vertex at $(0, 0)$.
2. Plot a second point at $(2, 3)$ (or $(-2, 3)$), then draw a smooth parabola through these points opening upwards.