Question

the graph of $y = -(x + 3)^2 + 4$ is shown in the $xy$-plane. what are the coordinates of the vertex of the parabola? choose 1 answer: a $(-5,0)$ b $(-3,4)$ c $(-1,0)$ d $(0,-5)$

Explanation:

Step1: Recall vertex form of parabola

The vertex form of a parabola is \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

Step2: Compare with given equation

The given equation is \( y = -(x + 3)^2 + 4 \). We can rewrite \( x + 3 \) as \( x - (-3) \). So comparing with \( y = a(x - h)^2 + k \), we have \( h=-3 \) and \( k = 4 \).

Answer:

B. \((-3, 4)\)