Question

the graphs below model two transverse waves that maya created with a battle rope. in each graph, the horizontal axis shows the horizontal position of particles of the rope, measured from where maya stood. the vertical axis shows the vertical displacement of the rope, measured from the equilibrium position, at a specific moment in time.
wave 1
wave 2
assuming the waves are traveling at the same speed, compare the waves.

	greater for wave 1	greater for wave 2	equal for both waves
the wavelength is	○	○	○
the frequency is	○	○	○

submit

Explanation:

Step1: Find Wave 1 amplitude

Amplitude is max displacement from equilibrium. For Wave 1, this is $1$ ft.

Step2: Find Wave 2 amplitude

For Wave 2, max displacement from equilibrium is $1$ ft.

Step3: Find Wave 1 wavelength

Wavelength is distance between two crests. Wave 1: distance from 0 to 10 is $10$ ft.

Step4: Find Wave 2 wavelength

Wave 2: distance from 0 to 15 is $15$ ft.

Step5: Relate frequency to speed/wavelength

Use formula $f=\frac{v}{\lambda}$, where $v$ (speed) is equal for both.

Step6: Compare frequencies

Since $v$ is constant, smaller $\lambda$ means larger $f$. Wave 1 has smaller $\lambda$, so larger $f$.

Answer:

	greater for Wave 1	greater for Wave 2	equal for both waves
The wavelength is		✅
The frequency is	✅