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Question
guided practice what are the foci of the graph \\(\frac{x^2}{24} - y^2 = 1\\)? a. (±25, 0) b. (±√24, 0) c. (±1, 0) d. (±5, 0)
Step1: Identify hyperbola standard form
The given equation $\frac{x^2}{24} - y^2 = 1$ matches the horizontal hyperbola form $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$.
Step2: Find $a^2$ and $b^2$
$a^2=24$, $b^2=1$
Step3: Calculate $c$ using $c^2=a^2+b^2$
$c^2=24+1=25$, so $c=\sqrt{25}=5$
Step4: State foci coordinates
For horizontal hyperbola, foci are $(\pm c,0)=(\pm5,0)$
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D. $(\pm5,0)$