Question

a hiker walks 11 km due north from camp and then turns and walks 11 km due east. what is the approximate displacement of the hiker from the camp? a 22 km north east b 10 km north east c 16 km north east d 8 km north east

Explanation:

Step1: Use Pythagorean theorem

The hiker moves 11 km north and 11 km east. The displacement $d$ from the starting - point (the camp) is given by $d=\sqrt{11^{2}+11^{2}}$.

Step2: Calculate the value

$d = \sqrt{121 + 121}=\sqrt{242}\approx15.6$ km. Since the hiker moves equal distances in the north and east directions, the direction is North - East. Among the options, the closest magnitude to 15.6 km is 16 km.

Answer:

c. 16 km North East