Question

c. $sqrt3{13x - 1} - 4 = 0$
hint: after adding 4, dont square both sides.

Explanation:

Step1: Isolate the cube root

Add 4 to both sides.
$$\sqrt[3]{13x - 1} = 4$$

Step2: Eliminate the cube root

Cube both sides of the equation.
$$(\sqrt[3]{13x - 1})^3 = 4^3$$
$$13x - 1 = 64$$

Step3: Solve for x

Add 1 to both sides, then divide by 13.
$$13x = 64 + 1 = 65$$
$$x = \frac{65}{13} = 5$$

Answer:

$x=5$