Question

homework 1: 1.1-1.4 review
score: 8/17 answered: 5/13
question 6
if
\\(\int_{-9}^{0} y(s) ds = 15\\)
and
\\(\int_{-6}^{0} y(s) ds = 10.5\\)
what does the following integral equal?
\\(\int_{-9}^{-6} y(s) ds = \\)

Explanation:

Step1: Use integral interval addition

$\int_{-9}^{0} y(s)ds = \int_{-9}^{-6} y(s)ds + \int_{-6}^{0} y(s)ds$

Step2: Rearrange to solve for target integral

$\int_{-9}^{-6} y(s)ds = \int_{-9}^{0} y(s)ds - \int_{-6}^{0} y(s)ds$

Step3: Substitute given values

$\int_{-9}^{-6} y(s)ds = 15 - 10.5$

Step4: Calculate the result

$\int_{-9}^{-6} y(s)ds = 4.5$

Answer:

$4.5$