Question

3.3 homework - reflections and translations - graded
the vertices of a quadrilateral are:
a(-4, -2), b(-5, 3), c(6, 2), d(9, -1)
find the coordinates after the quadrilateral is translated up 2 units and left 1 unit.

Explanation:

Step1: Recall translation rule

For a translation left \(h\) units and up \(k\) units, the rule for a point \((x,y)\) is \((x - h,y + k)\). Here \(h = 1\) and \(k=2\).

Step2: Translate point A

For \(A(-4,-2)\), \(x=-4\), \(y = - 2\). Using the rule \((x - 1,y + 2)\), we get \(A'(-4-1,-2 + 2)=A'(-5,0)\).

Step3: Translate point B

For \(B(-5,3)\), \(x=-5\), \(y = 3\). Using the rule \((x - 1,y + 2)\), we get \(B'(-5-1,3 + 2)=B'(-6,5)\).

Step4: Translate point C

For \(C(6,2)\), \(x = 6\), \(y=2\). Using the rule \((x - 1,y + 2)\), we get \(C'(6-1,2 + 2)=C'(5,4)\).

Step5: Translate point D

For \(D(9,-1)\), \(x = 9\), \(y=-1\). Using the rule \((x - 1,y + 2)\), we get \(D'(9-1,-1 + 2)=D'(8,1)\).

Answer:

A'(-5,0)
B'(-6,5)
C'(5,4)
D'(8,1)