Question

how many times does 7 go into 9? time, with a remainder of ? \\(\

$$\begin{array}{r}\\ ? \\\\ 7 \\enclose{longdiv}{91}\\\\ \\end{array}$$

\\)

Explanation:

Step1: Divide 9 by 7

We know that \( 7\times1 = 7 \), and \( 9 - 7=2 \). So we check how many times 7 can be multiplied to get a number less than or equal to 9. Since \( 7\times1 = 7\leq9 \) and \( 7\times2 = 14>9 \), 7 goes into 9 1 time.

Step2: Find the remainder

To find the remainder, we subtract the product of the quotient and the divisor from the dividend. So \( 9 - 7\times1=9 - 7 = 2 \).

Answer:

1 time, with a remainder of 2