Question

1. as hudson swam across an 80 - meter river, the current carried him 30 meters downstream. how far did he swim?

Explanation:

Step1: Identify the right - triangle

The width of the river (80 meters) and the distance carried downstream (30 meters) form the two legs of a right - triangle, and the distance Hudson swam is the hypotenuse.

Step2: Apply the Pythagorean theorem

The Pythagorean theorem is \(a^{2}+b^{2}=c^{2}\), where \(a = 80\), \(b = 30\), and \(c\) is the distance Hudson swam. So \(c=\sqrt{80^{2}+30^{2}}\).

Step3: Calculate the value

First, calculate \(80^{2}=6400\) and \(30^{2}=900\). Then \(80^{2}+30^{2}=6400 + 900=7300\). So \(c=\sqrt{7300}\approx85.4\) meters.

Answer:

85.4 meters