Question

hw 7.3 (e - book 3.6) solving quadratic equations using the
question 3 of 8 (1 point) | question attempt: 1 of unlimited
solve by using the quadratic formula. express the solution set in exact si

$y^{2}-3y - 9 = 0$

part: 0 / 4

part 1 of 4

the equation is in the form $ax^{2}+bx + c = 0$.

$y^{2}-3y - 9 = 0$

identify the values of $a$, $b$, and $c$.

$a=square,b=square,c=square$

Explanation:

Step1: Identify coefficients

For the quadratic equation $y^{2}-3y - 9=0$ which is in the form $ay^{2}+by + c = 0$, we compare the terms.
$a = 1$, $b=-3$, $c=-9$

Answer:

$a = 1$, $b=-3$, $c=-9$