Question

identify the vertex, axis of symmetry, and direction of the graph of each function. compare the width of the graph to the width of the graph of ( f(x)=x^2 ).
( h(x) = -8(x + 1)^2 - 1 )
the vertex is (square).
(type an ordered pair.)

Explanation:

Step1: Recall vertex form of quadratic

The vertex form of a quadratic function is \( h(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex.

Step2: Compare with given function

Given \( h(x) = -8(x + 1)^2 - 1 \), rewrite \( x + 1 \) as \( x - (-1) \). So, \( h = -1 \) and \( k = -1 \).

Answer:

\((-1, -1)\)