Question

the inequality $-x^2 - 6 < 0$ has
0 critical points
1 critical point
2 critical points

Explanation:

Step1: Rewrite inequality to standard form

Rearrange the inequality: $-x^2 - 6 < 0 \implies x^2 + 6 > 0$

Step2: Find critical points (solve equality)

Solve $x^2 + 6 = 0 \implies x^2 = -6$

Step3: Analyze real solutions

No real numbers satisfy $x^2 = -6$, so there are no real critical points.

Answer:

0 critical points