Question

interpreting motion from graphs
rank the graphs from the least to the greatest distance traveled
c, a, b
c, a=b
a, c, b
a, b, c

Explanation:

Step1: Analyze graph A

In graph A, the position remains constant at 10 m throughout the 20 - sec time interval. So the distance traveled is 0 m.

Step2: Analyze graph B

In graph B, the object moves from the origin to 10 m and then back to the origin. The distance traveled is \(d_B=10 + 10=20\) m.

Step3: Analyze graph C

In graph C, the object moves from 10 m to 0 m. The distance traveled is \(d_C = 10\) m.

Step4: Rank the distances

Ranking from least to greatest: \(d_A=0\) m, \(d_C = 10\) m, \(d_B=20\) m. So the order is A, C, B.

Answer:

A. A, C, B