Question

the inverse of the following function? g(x)=6x+18

Explanation:

Step1: Replace $g(x)$ with $y$

$y = 6x + 18$

Step2: Swap $x$ and $y$

$x = 6y + 18$

Step3: Isolate the term with $y$

$x - 18 = 6y$

Step4: Solve for $y$

$y = \frac{x - 18}{6} = \frac{1}{6}x - 3$

Answer:

$g^{-1}(x)=\frac{1}{6}x - 3$