Question

1. if jl = 5x + 2, find jl.

27
3x - 1
j
k
l

Explanation:

Step1: Relate JL, JK, KL

From the line segment, \( JL = JK + KL \). Given \( JK = 27 \), \( KL = 3x - 1 \), and \( JL = 5x + 2 \). So, \( 5x + 2 = 27 + 3x - 1 \).

Step2: Solve for x

Simplify the equation: \( 5x + 2 = 3x + 26 \). Subtract \( 3x \) from both sides: \( 2x + 2 = 26 \). Subtract 2: \( 2x = 24 \). Divide by 2: \( x = 12 \).

Step3: Find JL

Substitute \( x = 12 \) into \( JL = 5x + 2 \): \( JL = 5(12) + 2 = 60 + 2 = 62 \).

Answer:

62