Question

joe and max shake hands and say goodbye. joe walks east 0.50 km to a coffee shop, and max flags a cab and rides north 3.50 km to a bookstore. part a how far apart are their destinations? express your answer in kilometers.

Explanation:

Step1: Identify the displacements

Joe moves east $x = 0.50$ km and Max moves north $y=3.50$ km. These are two - perpendicular displacements.

Step2: Apply the Pythagorean theorem

The distance $d$ between their destinations is given by $d=\sqrt{x^{2}+y^{2}}$. Substitute $x = 0.50$ km and $y = 3.50$ km into the formula: $d=\sqrt{(0.50)^{2}+(3.50)^{2}}=\sqrt{0.25 + 12.25}=\sqrt{12.5}$.

Step3: Calculate the value

$d=\sqrt{12.5}\approx3.54$ km.

Answer:

$3.54$ km