Question

a 0.9 kg soccer ball is kicked, changing its velocity from 2 m/s to 7 m/s. what is the impulse experienced by the soccer ball? the impulse experienced by the ball is ___ kg(m)/s j = δp or j = p_f - p_i

Explanation:

Step1: Recall impulse - momentum theorem

The impulse $J$ is equal to the change in momentum $\Delta P$. The formula for momentum is $P = mv$, where $m$ is mass and $v$ is velocity. So, $\Delta P=P_f - P_i=m(v_f - v_i)$.

Step2: Identify given values

We are given that $m = 0.9\ kg$, $v_i = 2\ m/s$, and $v_f=7\ m/s$.

Step3: Calculate the change in momentum

Substitute the values into the formula $\Delta P=m(v_f - v_i)$. So, $\Delta P=0.9\times(7 - 2)$.
$\Delta P=0.9\times5$.
$\Delta P = 4.5\ kg\cdot m/s$.

Answer:

$4.5$