Question

l2.3-2.5_alg2_cfu
what are the intercepts of 5x + 20y = 10
x- intercept ( , ) y - intercept ( , )
2 0 0 -2 1/2 -1/2

Explanation:

Step1: Find x - intercept (set y = 0)

Substitute \( y = 0 \) into the equation \( 5x+20y = 10 \). We get \( 5x+20\times0 = 10 \), which simplifies to \( 5x=10 \). Then, solve for \( x \) by dividing both sides by 5: \( x=\frac{10}{5}=2 \). So the x - intercept is \( (2,0) \).

Step2: Find y - intercept (set x = 0)

Substitute \( x = 0 \) into the equation \( 5x + 20y=10 \). We get \( 5\times0+20y = 10 \), which simplifies to \( 20y = 10 \). Then, solve for \( y \) by dividing both sides by 20: \( y=\frac{10}{20}=\frac{1}{2} \). So the y - intercept is \( (0,\frac{1}{2}) \).

Answer:

x - intercept: (2, 0)
y - intercept: (0, 1/2)