Question

a large diamond with a mass of 481.3 grams was recently discovered in a mine. if the density of the diamond is 3.51 $\frac{g}{cm^3}$, what is the volume? round your answer to the nearest hundredth. 48.23 cm³ 55.91 cm³ 58.71 cm³ 137.12 cm³

Explanation:

Step1: Recall density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. We need to solve for $V$, so we can re - arrange the formula to $V = \frac{m}{
ho}$.

Step2: Substitute given values

We are given that $m = 481.3$ grams and $
ho=3.51\frac{g}{cm^{3}}$. Substituting these values into the formula $V=\frac{m}{
ho}$, we get $V=\frac{481.3}{3.51}$.

Step3: Calculate the volume

$V=\frac{481.3}{3.51}\approx137.12$ $cm^{3}$.

Answer:

137.12 $cm^{3}$