Question

the length of a rectangle is four times its width. if the perimeter of the rectangle is 60 yd, find its length and width.
length: yd
width: yd

Explanation:

Step1: Define variables

Let the width of the rectangle be $w$ yards. Then the length $l = 4w$ yards.

Step2: Use perimeter formula

The perimeter formula of a rectangle is $P=2(l + w)$. Substitute $l = 4w$ and $P = 60$ into the formula: $60=2(4w+w)$.

Step3: Simplify the equation

First, simplify the right - hand side: $60=2(5w)=10w$.

Step4: Solve for $w$

Divide both sides of the equation $60 = 10w$ by 10: $w=\frac{60}{10}=6$ yards.

Step5: Solve for $l$

Since $l = 4w$, substitute $w = 6$ into the equation: $l=4\times6 = 24$ yards.

Answer:

length: 24 yd
width: 6 yd