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Question
let f(x) = 4x - 1, h(x) = -x + 2. find (h ∘ f)(6). (h ∘ f)(6) = \square
Step1: Find f(6)
To find \( f(6) \), substitute \( x = 6 \) into \( f(x)=4x - 1 \).
\( f(6)=4\times6 - 1=24 - 1 = 23 \)
Step2: Find h(f(6)) i.e., h(23)
Now substitute \( x = 23 \) into \( h(x)=-x + 2 \).
\( h(23)=-23 + 2=-21 \)
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