Question

let $g(x) = -4x$ and $h(x) = x^2 + 5$. find $(g \circ h)(0)$.

$(g \circ h)(0) = \square$ (simplify your answer.)

Explanation:

Step1: Compute h(0)

$h(0) = 0^2 + 5 = 5$

Step2: Substitute h(0) into g(x)

$g(h(0)) = g(5) = -4 \times 5$

Answer:

$-20$