Question

level k 〉 x.5 factor quadratics with leading co you have pri
factor.
$w^2 + 5w + 4$

Explanation:

Step1: Find pair summing to 5, product 4

Identify two numbers: 1 and 4, since $1+4=5$ and $1\times4=4$.

Step2: Split middle term and factor

Rewrite quadratic, then factor by grouping:

$$\begin{align*} w^2 + 5w + 4 &= w^2 + w + 4w + 4\\ &= w(w+1) + 4(w+1)\\ &= (w+1)(w+4) \end{align*}$$

Answer:

$(w+1)(w+4)$