Question

a light bulb has a resistance of 360 ω. what is the current in the bulb when it has a potential difference of 120 v across it?
○ 0.33 a
○ 3 a
○ 480 a
○ 43,200 a

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is given by \( I = \frac{V}{R} \), where \( I \) is the current, \( V \) is the potential difference (voltage), and \( R \) is the resistance.

Step2: Substitute the given values

We know that \( V = 120 \, \text{V} \) and \( R = 360 \, \Omega \). Substituting these values into the formula, we get \( I=\frac{120}{360} \).

Step3: Simplify the fraction

Simplifying \( \frac{120}{360} \), we divide both the numerator and the denominator by 120, which gives \( \frac{1}{3}\approx0.33 \, \text{A} \).

Answer:

0.33 A