Question

a light bulb has a resistance of 360 ω. what is the current in the bulb when it has a potential difference of 120 v across it?
0.33 a
3 a
480 a
43,200 a

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $I=\frac{V}{R}$, where $I$ is current, $V$ is potential - difference, and $R$ is resistance.

Step2: Substitute given values

Given $V = 120\ V$ and $R=360\ \Omega$. Substitute into the formula: $I=\frac{120}{360}=\frac{1}{3}\approx0.33\ A$.

Answer:

0.33 A