Question

lina is planning to paint a building whose dimensions are shown below. the front of the building has a door measuring 48 in by 80 in. the left and right sides of the building each have 2 windows measuring 5 ft by 4 ft each. the back of the building has no window or door. use the given information to answer the questions. each tab shows a different view of the building. front - right view back - left view conversion facts for length 1 foot (ft) = 12 inches (in) 1 yard (yd) = 3 feet (ft) 1 yard (yd) = 36 inches (in) (a) assuming the roof, windows, and door require no paint, what is the area in square feet that needs paint? (do not round any intermediate computations and give your answer as a whole number.)

Explanation:

Step1: Calculate front - wall area

The front - wall is a rectangle with dimensions 18 ft (width) and 9 ft (height). The area of a rectangle is $A = lw$. So, the area of the front - wall is $A_{front}=18\times9 = 162$ square feet.

Step2: Calculate door area

The door has dimensions 4 ft (width) and 8 ft (height). The area of the door is $A_{door}=4\times8 = 32$ square feet.

Step3: Calculate side - wall area

Each side - wall has dimensions 9 ft (height) and 40 ft (length). The area of one side - wall is $A_{side}=9\times40 = 360$ square feet. Since there are 2 side - walls, the total side - wall area is $A_{sides}=2\times360 = 720$ square feet.

Step4: Calculate window area

Each window has dimensions 5 ft (width) and 4 ft (height). There are 2 windows on each side - wall, so 4 windows in total. The area of one window is $A_{window}=5\times4 = 20$ square feet. The total window area is $A_{windows}=4\times20 = 80$ square feet.

Step5: Calculate the area to be painted

The area to be painted is the sum of the front - wall area and side - wall areas minus the door and window areas. $A = A_{front}+A_{sides}-A_{door}-A_{windows}=162 + 720-32 - 80=770$ square feet.

Answer:

770