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a line has a slope of -5 and includes the points (0, p) and (1, 5). wha…

Question

a line has a slope of -5 and includes the points (0, p) and (1, 5). what is the value of p?
p =
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Explanation:

Step1: Recall slope formula

The slope $m$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $m=\frac{y_2-y_1}{x_2-x_1}$.

Step2: Substitute known values

Let $(x_1,y_1)=(0,p)$, $(x_2,y_2)=(1,5)$, and $m=-5$.
$\displaystyle -5=\frac{5-p}{1-0}$

Step3: Simplify and solve for $p$

Simplify denominator: $1-0=1$, so $-5=5-p$.
Rearrange to solve for $p$: $p=5+5$

Answer:

$10$