Question

listen
solve the system of equations.
$\begin{cases} y=2x \\ y=x^{2}-x-4 end{cases}$
use the keypad to enter your answers in the boxes.
the solutions of the equations are: ( $square$ ) and ( $square$ ).

Explanation:

Step1: Substitute $y=2x$ into quadratic equation

$2x = x^2 - x - 4$

Step2: Rearrange to standard quadratic form

$x^2 - 3x - 4 = 0$

Step3: Factor the quadratic equation

$(x-4)(x+1) = 0$

Step4: Solve for $x$ values

$x-4=0 \implies x=4$; $x+1=0 \implies x=-1$

Step5: Find corresponding $y$ values

For $x=4$: $y=2(4)=8$; For $x=-1$: $y=2(-1)=-2$

Answer:

$(4, 8)$ and $(-1, -2)$