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on this map, oxford street is perpendicular to the street intersections…

Question

on this map, oxford street is perpendicular to

the street intersections form right angles.

street is perpendicular to

Explanation:

Step1: Recall Perpendicular Definition

Perpendicular lines intersect at \(90^\circ\) (right angles). In a grid - like street map, horizontal and vertical streets are perpendicular.

Step2: Analyze Oxford St.

Oxford St. is a horizontal street (from the map's layout). The vertical streets (like Rosewood St., Womden Bl.) will be perpendicular to it. Looking at the map, Oxford St. is horizontal, so it is perpendicular to the vertical streets (Rosewood St., Womden Bl. etc.). For the first blank, since Oxford St. is horizontal, it is perpendicular to the vertical streets (e.g., Rosewood St. or Womden Bl.). Let's assume the first part: Oxford Street is perpendicular to Rosewood St. (or Womden Bl., depending on the map's exact layout, but from the grid, vertical streets to horizontal Oxford St.).

Step3: Analyze the other street (let's say the second street, maybe a vertical one)

If we take a vertical street (like Rosewood St.), it will be perpendicular to the horizontal streets (George St., Oak St., Oxford St.). So if the second street is a vertical one, it is perpendicular to the horizontal streets.

Answer:

  1. Oxford Street is perpendicular to Rosewood St. (or Womden Bl., or other vertical streets on the map)
  2. [Name of vertical street] is perpendicular to George St. (or Oak St., or Oxford St., horizontal streets on the map)

(Note: The exact answers depend on the precise labels of the vertical and horizontal streets in the map. The key is that horizontal and vertical streets are perpendicular as they form right angles at intersections.)