Question

if the mass of the egg is 0.60 kg, its initial speed is 1.2 m/s, and the time to stop is 1.2 s. find the average force on the egg. express your answer to two significant figures and include the appropriate units. $f_{avg}=$ value units

Explanation:

Step1: Identify the formula for average force

The formula for average force is $F_{avg}=\frac{\Delta p}{\Delta t}$, where $\Delta p = m\Delta v$ (change in momentum), $m$ is mass, $\Delta v$ is change in velocity and $\Delta t$ is time interval. The egg stops, so $\Delta v=v_f - v_i$, with $v_f = 0\ m/s$ and $v_i=1.2\ m/s$.

Step2: Calculate the change in momentum

$\Delta p=m(v_f - v_i)$. Substitute $m = 0.60\ kg$, $v_f = 0\ m/s$ and $v_i = 1.2\ m/s$ into the formula. $\Delta p=0.60\times(0 - 1.2)=- 0.72\ kg\cdot m/s$.

Step3: Calculate the average force

$F_{avg}=\frac{\Delta p}{\Delta t}$. Substitute $\Delta p=- 0.72\ kg\cdot m/s$ and $\Delta t = 1.2\ s$ into the formula. $F_{avg}=\frac{-0.72}{1.2}=- 0.60\ N$. The negative sign indicates the direction of the force is opposite to the initial - velocity direction of the egg. We take the magnitude for the value of the average force.

Answer:

$0.60\ N$