Question

math:
\choose one & solve: youre the teacher\
directions: pick one of the following math problems, and take a video of yourself solving the
problem. explain the steps you are taking as you are solving, as if you were the teacher. post your
video in the google classroom under this assignment.

1. $-10 - (-36) =$
2. $3x - (-3) = 18$
3. $4x + 2 + 2(5x - 1)$

Explanation:

Let's choose to solve problem 1: \(-10 - (-36)\)

Step1: Recall the rule of subtracting a negative number

Subtracting a negative number is equivalent to adding its positive counterpart. So, \(-10 - (-36)\) can be rewritten as \(-10 + 36\).

Step2: Perform the addition

Now, we calculate \(-10 + 36\). Since \(36\) is positive and has a greater absolute value than \(-10\), we subtract the absolute values: \(36 - 10 = 26\), and the result takes the sign of the number with the greater absolute value (which is positive here).

Step1: Simplify the left - hand side

Subtracting a negative number is like adding a positive number. So, \(3x-(-3)=3x + 3\). The equation becomes \(3x + 3=18\).

Step2: Isolate the term with \(x\)

Subtract 3 from both sides of the equation: \(3x+3 - 3=18 - 3\). This simplifies to \(3x = 15\).

Step3: Solve for \(x\)

Divide both sides of the equation by 3: \(\frac{3x}{3}=\frac{15}{3}\). So, \(x = 5\).

Step1: Distribute the 2 in \(2(5x - 1)\)

Using the distributive property \(a(b + c)=ab+ac\), we have \(2(5x-1)=2\times5x-2\times1 = 10x-2\). The expression becomes \(4x + 2+10x-2\).

Step2: Combine like terms

Combine the \(x\) - terms: \(4x+10x = 14x\). Combine the constant terms: \(2-2 = 0\). So the simplified expression is \(14x\).

Answer:

\(26\)

If we choose problem 2: \(3x - (-3) = 18\)