Question

1. $7^{3} \div 7 = \frac{7^{3}}{7} = 7^{2}$
2. $\frac{14^{6}}{14^{4}} = 14^{2}$
3. $\frac{x^{9}}{x^{5}} = x^{4}$
4. $\frac{h^{15}}{h^{12}} = h^{3}$
5. $\frac{10y^{11}}{5y^{4}} =$
6. $\frac{64k^{9}}{8k} =$
7. $\frac{4x^{8} \bullet y^{5}}{2x^{4} \bullet y^{2}} =$

Explanation:

Step1: Simplify coefficients first

$\frac{10}{5} = 2$

Step2: Apply exponent rule to $y$

$y^{11-4}=y^7$

Step3: Combine results for Q5

$2 \cdot y^7 = 2y^7$

Step1: Simplify coefficients first

$\frac{64}{8} = 8$

Step2: Apply exponent rule to $k$

$k^{9-1}=k^8$

Step3: Combine results for Q6

$8 \cdot k^8 = 8k^8$

Step1: Simplify coefficients first

$\frac{4}{2} = 2$

Step2: Apply exponent rule to $x$

$x^{8-4}=x^4$

Step3: Apply exponent rule to $y$

$y^{5-2}=y^3$

Step4: Combine results for Q7

$2 \cdot x^4 \cdot y^3 = 2x^4y^3$

Answer:

1. $2y^7$
2. $8k^8$
3. $2x^4y^3$