Question

1. if 6 + 5 = 7 + 3 + 1, then 6 + 5 - 4 = 7 + 3 + 1 - 4.

Explanation:

Step1: Analyze the given equation

We are given that \(6 + 5=7 + 3+1\). Let's denote the left - hand side of the first equation as \(L = 6 + 5\) and the right - hand side as \(R=7 + 3 + 1\). So we know that \(L = R\).

Step2: Apply the subtraction property of equality

The subtraction property of equality states that if \(a=b\), then \(a - c=b - c\) for any real number \(c\). In our case, \(a = L=6 + 5\), \(b = R = 7+3 + 1\) and \(c = 4\). So when we subtract 4 from both sides of the equation \(L = R\) (i.e., \(6 + 5=7 + 3+1\)), we get \(6 + 5-4=7 + 3+1-4\).

Answer:

This statement is correct (it follows the subtraction property of equality: if \(a = b\), then \(a - c=b - c\) for any real number \(c\)).