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12a. $(w^{2}-25z^{2})=(w-5z)(w+5z)$

Question

12a. $(w^{2}-25z^{2})=(w-5z)(w+5z)$

Explanation:

Step1: Recognize difference of squares

Note that $w^2 - 25z^2 = w^2 - (5z)^2$, which matches $a^2 - b^2$.

Step2: Apply difference of squares formula

Use $a^2 - b^2=(a-b)(a+b)$, where $a=w$, $b=5z$.

$$\begin{align*} w^2 - (5z)^2&=(w-5z)(w+5z) \end{align*}$$

Answer:

The equation confirms the factorization of a difference of squares, and the equality is verified as correct.