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Question
- \\(dfrac{3m^{-4}}{m^{3}}\\)
Step1: Apply exponent division rule
When dividing terms with the same base, subtract exponents: $\frac{m^a}{m^b}=m^{a-b}$. Here, the base is $m$, so we calculate the exponent of $m$ as $-4 - 3$.
$\frac{3m^{-4}}{m^3}=3m^{-4-3}$
Step2: Simplify the exponent
Compute $-4 - 3$ to get the new exponent for $m$.
$3m^{-7}$
Step3: Rewrite with positive exponent
Use the rule $m^{-n}=\frac{1}{m^n}$ to convert to positive exponent form.
$3 \cdot \frac{1}{m^7}=\frac{3}{m^7}$
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$\frac{3}{m^7}$ (or $3m^{-7}$)