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3. $\frac{2}{3}+\frac{1}{6}=$ $\frac{1}{3}$ $\frac{1}{2}$ $\frac{1}{9}$…

Question

  1. $\frac{2}{3}+\frac{1}{6}=$

$\frac{1}{3}$
$\frac{1}{2}$
$\frac{1}{9}$
$\frac{5}{6}$

Explanation:

Step1: Find a common denominator

The common - denominator of 3 and 6 is 6. Rewrite $\frac{2}{3}$ with a denominator of 6. Since $3\times2 = 6$, then $\frac{2}{3}=\frac{2\times2}{3\times2}=\frac{4}{6}$.

Step2: Add the fractions

Now we have $\frac{4}{6}+\frac{1}{6}$. According to the rule of adding fractions with the same denominator $\frac{a}{c}+\frac{b}{c}=\frac{a + b}{c}$, so $\frac{4}{6}+\frac{1}{6}=\frac{4 + 1}{6}=\frac{5}{6}$.

Answer:

$\frac{5}{6}$